Uber SWE I Online Assessment – Jan 2026
- Posted
- 15 Mar 2026
Summary
I underwent the Uber SWE I Online Assessment, a disqualification round featuring three distinct algorithmic problems covering graph theory, number theory, and advanced data structures. I tackled problems related to minimum spanning trees, connected components using prime factorization, and finding k-th greater elements using a segment tree.
How it went
Online Assessment (Disqualification Round)
Duration: 65 minutes
Questions asked (3)
- 01
Uber City Network Construction - Minimum Spanning Tree
Data Structures & Algorithms
Problem 1 — Uber City Network Construction
Uber is expanding its infrastructure to support faster dispatching across a city. The city is represented as a coordinate grid where n hubs are located at coordinates:
(x_i, y_i)You can connect any two hubs i and j with a direct communication link.
The cost of connecting two hubs is defined as:
min(|x_i - x_j|, |y_i - y_j|)Determine the minimum total cost required to connect all hubs so that every hub can communicate with every other hub either directly or indirectly.
Constraints
2 ≤ n ≤ 10^50 ≤ x_i, y_i ≤ 10^9
- 02
Uber Zone Clusters - Prime Factorization & DSU
Data Structures & Algorithms
Problem 2 — Uber Zone Clusters
Uber optimizes driver dispatch by analyzing connectivity between city zones.
Each zone
ihas a traffic signature:S_iTwo zones are considered directly connected if:
gcd(S_i, S_j) > 1Connectivity is transitive, meaning if zone
Aconnects toBandBconnects toC, all belong to the same cluster.Task
Given an array of
nsignatures, return an array where each element represents the size of the cluster to which that zone belongs. - 03
Uber Demand Trend Analysis - k-th Element to the Right
Data Structures & Algorithms
Problem 3 — Uber Demand Trend Analysis
You are given an array of integers:
demandLevelsFor each index
i, determine the index of the k-th element to the right (j > i) such that:demandLevels[j] > demandLevels[i]If such an element does not exist, return -1.
Output indices follow 1-based indexing.
Constraints
1 ≤ n ≤ 10^51 ≤ k ≤ 501 ≤ demandLevels[i] ≤ 10^9